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The number of do­ mains defined in the parametric space, which is 7 dimensional, is therefore also equal to 3. The strong separator defined in (48) thus esta­ blishes three connected domains, and the identi­ fication problem has precisely 3 distinct solutions. i v' We know that the determinant of matrix K C K is zero in subsets wich dimension (d-1) where d is the parameter space dimension. These subsets are called separators and divide parametric space in­ to several parts. If the equations are linear the separators define two distinct parts, but for non-linear equations the number of regions thus formes may exceed two.

Both measurement gains have been assumed known. 4) we see a 4 5 » °25 35 this gives 6 equations in 6 unknowns, including IV P 8' P '12· This is represented in the last row of Table 1, where the 2nd column gives the subscripts of those elements of P involved and the last column equals, (the number of unknowns)-(the number of equations) bolumns TABLE 1 indices of V ~ i No. of unknownsNo. of equations 7 3 2 -1 1,3,4,5,7,8,9,11,12 1,2,5,6,9,10 1,2,5,6,9,10 3,7,11 4,8,12 1 2 3 4 5 o This table suggests a method (B) analysis might prove useful on columns 4 and 5.

R together with the unknown 1 Also, entries of P in columns k, k φ i s if this does not include k = j , which can only occur if a.. e. if compartment j is a trap, the unknowns in column j of P - 1 must be added. , ψ 0, the total number of unknowns 3D can simply be found by adding to the number of nonzero entries in the jth column of A, the number of unknown elements in P lying in columns with the same index as the rows_in which the forementioned nonzero entries of A lie. k Ï j £/ A =_1, 2,. , s together with the unknown entries of P in rows k, k φ j .

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